2094. Finding 3-Digit Even Numbers

public class Solution
{
    public int[] FindEvenNumbers(int[] digits)
    {
        List<int> ans = new List<int>();
        int[] count = new int[10];

        foreach (var digit in digits)
            ++count[digit];

        // Try to construct `abc`.
        for (int a = 1; a <= 9; ++a)
        {
            for (int b = 0; b <= 9; ++b)
            {
                for (int c = 0; c <= 8; c += 2)
                {
                    if (count[a] > 0 && count[b] > (b == a ? 1 : 0) &&
                        count[c] > (c == a ? 1 : 0) + (c == b ? 1 : 0))
                        ans.Add(a * 100 + b * 10 + c);
                }
            }
        }

        return ans.ToArray();
    }
}