1465. Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts
UnknownView on LeetCode
Time: O(n log n)
Space: O(1)
Problem Overview
Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts (Unknown) asks you to solve a structured algorithmic task. This is a common Array / Greedy pattern in coding interviews. Sort cuts; find max gap in horizontal and vertical cuts; answer = maxGapH × maxGapV mod 10^9+7.
A full step-by-step explanation is being added. See the study guide for pattern-based practice.
Approach
Sort cuts; find max gap in horizontal and vertical cuts; answer = maxGapH × maxGapV mod 10^9+7.
1465.cs
C#
// Approach: Sort cuts; find max gap in horizontal and vertical cuts; answer = maxGapH × maxGapV mod 10^9+7.
// Time: O(n log n) Space: O(1)
public class Solution
{
public int MaxArea(int h, int w, int[] horizontalCuts, int[] verticalCuts)
{
const int kMod = 1_000_000_007;
Array.Sort(horizontalCuts);
Array.Sort(verticalCuts);
// the maximum gap of each direction
int maxGapX = Math.Max(verticalCuts[0], w - verticalCuts[verticalCuts.Length - 1]);
int maxGapY = Math.Max(horizontalCuts[0], h - horizontalCuts[horizontalCuts.Length - 1]);
for (int i = 1; i < verticalCuts.Length; ++i)
maxGapX = Math.Max(maxGapX, verticalCuts[i] - verticalCuts[i - 1]);
for (int i = 1; i < horizontalCuts.Length; ++i)
maxGapY = Math.Max(maxGapY, horizontalCuts[i] - horizontalCuts[i - 1]);
return (int)((long)maxGapX * maxGapY % kMod);
}
}Was this solution helpful?
Related Problems
- 4. Median of Two Sorted Arrays(Hard)
- 11. Container With Most Water(Medium)
- 15. 3Sum(Medium)
- 16. 3Sum Closest(Medium)
- 26. Remove Duplicates from Sorted Array(Easy)
- 27. Remove Element(Easy)