DDSA Solutions

1878. Get Biggest Three Rhombus Sums in a Grid

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Approach

For each cell try all rhombus sizes; compute border sums with diagonal prefix sums; track top 3.

Key Techniques

Array

Array problems involve manipulating elements stored in a contiguous block of memory. Key techniques include two-pointer traversal, prefix sums, sliding windows, and in-place partitioning. In C#, arrays are zero-indexed and fixed in size — use List<T> when you need dynamic resizing.

Greedy

Greedy algorithms make locally optimal choices at each step, hoping to reach a global optimum. Greedy works when a problem has the "greedy choice property" and "optimal substructure". Common applications: interval scheduling, activity selection, Huffman coding, and jump game.

Matrix

Matrix problems often involve BFS/DFS flood fill, dynamic programming on 2D grids, or spiral/diagonal traversal. For row × column DP, break it into 1D sub-problems column by column. Common pitfalls: boundary checks and modifying the input matrix in-place.

1878.cs
C#
// Approach: For each cell try all rhombus sizes; compute border sums with diagonal prefix sums; track top 3.
// Time: O(mn * min(m,n)) Space: O(mn)

public class Solution
{
    public int[] GetBiggestThree(int[][] grid)
    {
        int m = grid.Length;
        int n = grid[0].Length;
        SortedSet<int> sums = new SortedSet<int>();

        for (int i = 0; i < m; ++i)
        {
            for (int j = 0; j < n; ++j)
            {
                for (int sz = 0; i + sz < m && i - sz >= 0 && j + 2 * sz < n; ++sz)
                {
                    int sum = sz == 0 ? grid[i][j] : GetSum(grid, i, j, sz);
                    sums.Add(sum);
                    if (sums.Count > 3)
                        sums.Remove(sums.Min);
                }
            }
        }

        return sums.Reverse().ToArray();
    }

    // Returns the sum of the rhombus, where the top grid is (i, j) and the edge size is `sz`.
    private int GetSum(int[][] grid, int i, int j, int sz)
    {
        int x = i;
        int y = j;
        int sum = 0;

        // Go left down.
        for (int k = 0; k < sz; ++k)
            sum += grid[--x][++y];

        // Go right down.
        for (int k = 0; k < sz; ++k)
            sum += grid[++x][++y];

        // Go right up.
        for (int k = 0; k < sz; ++k)
            sum += grid[++x][--y];

        // Go left up.
        for (int k = 0; k < sz; ++k)
            sum += grid[--x][--y];

        return sum;
    }
}
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