892. Surface Area of 3D Shapes
MediumView on LeetCode
Time: O(n²)
Space: O(1)
Problem Overview
Each stack of h cubes: top and bottom faces plus 4 sides minus shared internal faces.
Intuition
Each stack of h cubes: top and bottom faces plus 4 sides minus shared internal faces. Adjacent stacks reduce area by 2*min(h1,h2).
Algorithm
- 1For each cell with h>0: add 2 + 4*h.
- 2For each adjacent cell pair: subtract 2*min(h1,h2).
Common Pitfalls
- •Count both top and bottom (2), plus 4*h sides, minus internal vertically stacked faces already handled by 4h+2 formula.
892.cs
C#
// Approach: Per cell contribute 4·h+2 faces; subtract 2·min(h, neighbor) for each shared wall with adjacent cells.
// Time: O(n²) Space: O(1)
public class Solution
{
public int SurfaceArea(int[][] grid)
{
int ans = 0;
int n = grid.Length;
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
if (grid[i][j] > 0)
ans += grid[i][j] * 4 + 2;
if (i > 0)
ans -= Math.Min(grid[i][j], grid[i - 1][j]) * 2;
if (j > 0)
ans -= Math.Min(grid[i][j], grid[i][j - 1]) * 2;
}
}
return ans;
}
}Was this solution helpful?
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