Total count
JavaView on GFG
Advertisement
Intuition
Count elements <= p and elements that need to be replaced to keep array sorted with bounded differences.
Algorithm
- 1Sort and binary search for elements <= p. Count is upper_bound(p) index.
Common Pitfalls
- •Depends on exact problem variant. Common: count of elements <= threshold using binary search on sorted array.
Total count.java
Java
// Approach: Count elements satisfying the given condition, often using binary search or linear scan.
// Time: O(n log n) Space: O(1)
class Solution {
int totalCount(int k, int[] arr) {
int count = 0;
for (int num : arr)
count += (num + k - 1) / k;
return count;
}
}Advertisement
Was this solution helpful?