3350. Adjacent Increasing Subarrays Detection II
MediumView on LeetCode
Time: O(n)
Space: O(1)
Problem Overview
Adjacent Increasing Subarrays Detection II (Medium) asks you to solve a structured algorithmic task. This is a common Array pattern in coding interviews. Binary search on k; check adjacent increasing subarrays of length k exist.
A full step-by-step explanation is being added. See the study guide for pattern-based practice.
Approach
Binary search on k; check adjacent increasing subarrays of length k exist.
Related patterns: Array
3350.cs
C#
// Approach: Binary search on k; check adjacent increasing subarrays of length k exist.
// Time: O(n) Space: O(1)
public class Solution
{
public int MaxIncreasingSubarrays(IList<int> nums)
{
int maxLength = 0;
int previousLength = 0;
int currentLength = 0;
int n = nums.Count;
for (int i = 0; i < n; i++)
{
currentLength++;
if (i == n - 1 || nums[i] >= nums[i + 1])
{
maxLength = Math.Max(maxLength,
Math.Max(currentLength / 2,
Math.Min(previousLength, currentLength)));
previousLength = currentLength;
currentLength = 0;
}
}
return maxLength;
}
}Was this solution helpful?
Related Problems
- 4. Median of Two Sorted Arrays(Hard)
- 11. Container With Most Water(Medium)
- 15. 3Sum(Medium)
- 16. 3Sum Closest(Medium)
- 26. Remove Duplicates from Sorted Array(Easy)
- 27. Remove Element(Easy)